Class X Ncert Maths
Exercise 4.4
Question 1:
Find the nature of the roots of the following quadratic equations.
If the real roots exist, find them;
(I) 2x2 −3x + 5 = 0
(II)
(III) 2x2 − 6x + 3 = 0
We know that for a quadratic equation ax2 + bx + c = 0, discriminant is b2 − 4ac.
(A) If b2 − 4ac > 0 → two distinct real roots
(B) If b2 − 4ac = 0 → two equal real roots
(C) If b2 − 4ac < 0 → no real roots
(I) 2x2 −3x + 5 = 0
Comparing this equation with ax2 + bx + c = 0, we obtain
a = 2, b = −3, c = 5
Discriminant = b2 − 4ac = (− 3)2 − 4 (2) (5) = 9 − 40
= −31
As b2 − 4ac < 0,
Therefore, no real root is possible for the given equation.
(II)
Comparing this equation with ax2 + bx + c = 0, we obtain
Discriminant
= 48 − 48 = 0
As b2 − 4ac = 0,
Therefore, real roots exist for the given equation and they are equal to each other.
And the roots will be
Therefore, the roots are
.
(III) 2x2 − 6x + 3 = 0
Comparing this equation with ax2 + bx + c = 0, we obtain
a = 2, b = −6, c = 3
Discriminant = b2 − 4ac = (− 6)2 − 4 (2) (3)
= 36 − 24 = 12
As b2 − 4ac > 0,
Therefore, distinct real roots exist for this equation as follows.
Therefore, the roots are
.
Question 2:
Find the values of k for each of the following quadratic equations, so that they have two equal roots.
(I) 2x2 + kx + 3 = 0
(II) kx (x − 2) + 6 = 0
We know that if an equation ax2 + bx + c = 0 has two equal roots, its discriminant
(b2 − 4ac) will be 0.
(b2 − 4ac) will be 0.
(I) 2x2 + kx + 3 = 0
Comparing equation with ax2 + bx + c = 0, we obtain
a = 2, b = k, c = 3
Discriminant = b2 − 4ac = (k)2− 4(2) (3)
= k2 − 24
For equal roots,
Discriminant = 0
k2 − 24 = 0
k2 = 24
(II) kx (x − 2) + 6 = 0
or kx2 − 2kx + 6 = 0
Comparing this equation with ax2 + bx + c = 0, we obtain
a = k, b = −2k, c = 6
Discriminant = b2 − 4ac = (− 2k)2 − 4 (k) (6)
= 4k2 − 24k
For equal roots,
b2 − 4ac = 0
4k2 − 24k = 0
4k (k − 6) = 0
Either 4k = 0 or k = 6 = 0
k = 0 or k = 6
However, if k = 0, then the equation will not have the terms ‘x2’ and ‘x’.
Therefore, if this equation has two equal roots, k should be 6 only.