Class 10 NCERT Maths Solution Exercise-5.3, Arithmetic Progression(A.P).


NCERT MATHS CLASS - X
Arithmetic Progressions 
Exercise 5.3



Question 15:
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc., the penalty for each succeeding day being Rs. 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days.

Sol.
From the question, the penalties are 200, 250, 300 ….. for 1st ,2nd , 3rd day and so on, it can be concluded that the penalties are in A.P with first term 200 and common difference 50.
A.P is 200, 250, 300, ………
Here, a = 200, d = 50
Penalty has to be paid for delaying the work by 30 days = S30
= 15 [400 + 1450]
= 15 (1850)
= 27750
Therefore, the contractor has to pay Rs 27750 as penalty.

Question 16:
A sum of Rs 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is Rs 20 less than its preceding prize, find the value of each of the prizes.

Sol.
Let the cost of 1st prize be P.
Cost of 2nd prize = P − 20
And cost of 3rd prize = P − 40
The costs of these prizes are in A.P with common difference −20 and first term P.
a = P, d = −20
Given that, S7 = 700
a + 3(−20) = 100
a − 60 = 100
a = 160
Therefore, the value of each of the prizes was Rs 160, Rs 140, Rs 120, Rs 100, Rs 80, Rs 60, and Rs 40.

Question 17:
In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of class I will plant 1 tree, a section of class II will plant 2 trees and so on till class XII. There are three sections of each class. How many trees will be planted by the students?

Sol.
The number of trees planted by the students is in AP.
1, 2, 3, 4, 5………………..12
First term, a = 1
Common difference, d = 2 − 1 = 1
= 6 (2 + 11)
= 6 (13)
= 78
Therefore, number of trees planted by 1 section of the classes = 78
Number of trees planted by 3 sections of the classes = 3 × 78 = 234
Therefore, 234 trees will be planted by the students.


Previous Q.11,12..                                                                                 Next Q.18,19..
 

Copyright © 2014. CBSE MBA COLLEGE - All Rights Reserved Powered by Forsaleinfos Classifieds IndiaClassifieds India